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a) How far up the incline will it move before coming to rest?

b) Will it slide down again?

So when it comes at rest, Vy = 0, Vx = 0

Since it slides down at a constant velocity, the angle must be such that the force of friction allows it to slide down without an applied force. So I believe it will slide down again.

y = Voyt - (1/2)gt^2

x = Voxt

tanA = y/x

I'm not too sure how to proceed from here, I know I will have to solve for time to get the distance in other terms